HYDROCARBONS QUIZ-14
Dear Readers,
The one subject in NEET which is candidates who can easily attain good marks is Chemistry. That's the reason, often, one doesn’t pay notice and choose to compromise it. But if one wants to rank above others, the tip is to be thorough with NEET chemistry concepts. The understanding of reactions and definite basic understanding is what requires major attention in Chemistry but once done it only gets simpler from there. The main focus on the to-do list should be on getting a hang of the NCERT syllabus of NEET chemistry..
Q1. Alkyl halides get converted to alkenes through:
Solution
(c)
(c)
Q2.According to Huckel’s rule an aromatic compound must possess
Solution
(b)
According to Huckel’s rule, the molecules which contain (4n+2)Ï€-electrons are aromatic.
(b)
According to Huckel’s rule, the molecules which contain (4n+2)Ï€-electrons are aromatic.
Q3. When n-hexane/n-heptane is passed through Cr2O3 supported over alumina at 600C gives:
Solution
(c)
The process is called aromatization.
(c)
The process is called aromatization.
Q4. The treatment of CH3MgX with CH3C≡C-H produces
- CH3-CH=CH2
- CH3C≡C-CH3
-
- CH4
Solution
(d) Terminal alkyne has acidic hydrogen which is enough to protonate the Grignard reagent. CH3MgX+CH3C≡CH → CH4+CH3C≡CMgX
(d) Terminal alkyne has acidic hydrogen which is enough to protonate the Grignard reagent. CH3MgX+CH3C≡CH → CH4+CH3C≡CMgX
Q5. The compound (CH3)2 CH—CHCl—CH3 reacts with alcoholic KOH to give the following alkene:
Solution
(d)
Follow Saytzeff rule of elimination.
(d)
Follow Saytzeff rule of elimination.
Q6. The product obtained when methyl magnesium bromide reacts with methyl alcohol is:
Solution
(c)
(c)
Q7. Aromatization of n-heptane and n-octane gives respectively:
Solution
(a)
n-heptane gives toluene; n-octane gives ethyl benzene.
(a)
n-heptane gives toluene; n-octane gives ethyl benzene.
Q8. The presence of unsaturation (olefinic or acetylinic bond) in an organic compound can be tested with:
Solution
(d)
Unsaturated molecules decolourise Baeyer’s reagent.
(d)
Unsaturated molecules decolourise Baeyer’s reagent.
Q9.CH≡CH+HBr→X, product X is
Solution
(b)
CH≡CH+HBr→CH2=CHBr
(b)
CH≡CH+HBr→CH2=CHBr
Q10. Which is not true in the case of natural gas?
Solution
(c)
Natural gas is a mixture of 80% CH4 and 10% C2H6+10% higher hydrocarbons.
(c)
Natural gas is a mixture of 80% CH4 and 10% C2H6+10% higher hydrocarbons.
