As per analysis for previous years, it has been observed that students preparing for NEET find Physics out of all the sections to be complex to handle and the majority of them are not able to comprehend the reason behind it. This problem arises especially because these aspirants appearing for the examination are more inclined to have a keen interest in Biology due to their medical background.
Furthermore, sections such as Physics are dominantly based on theories, laws, numerical in comparison to a section of Biology which is more of fact-based, life sciences, and includes substantial explanations. By using the table given below, you easily and directly access to the topics and respective links of MCQs. Moreover, to make learning smooth and efficient, all the questions come with their supportive solutions to make utilization of time even more productive. Students will be covered for all their studies as the topics are available from basics to even the most advanced. .
Q1. The area of the region covered by the TV broadcast by a TV tower of 100 m height is (radius of the earth =6.4×106 m)
Solution
Area covered by T.V. signals A=2Ï€hR=2×3.14×100×6.4×106=128Ï€×108 ⇒A=1.28Ï€×103 km2
Area covered by T.V. signals A=2Ï€hR=2×3.14×100×6.4×106=128Ï€×108 ⇒A=1.28Ï€×103 km2
Q2.The sky wave propagation is suitable for radio-waves of frequency
Solution
The sky waves are the radiowaves of frequency between 2 MHz to 30 MHz. These waves can propagate through atmosphere but reflected back by the ionosphere of earth’s atmosphere. These waves can propagate from transmitter to receiver through sky, therefore, their propagation is called sky wave propagation.
The sky waves are the radiowaves of frequency between 2 MHz to 30 MHz. These waves can propagate through atmosphere but reflected back by the ionosphere of earth’s atmosphere. These waves can propagate from transmitter to receiver through sky, therefore, their propagation is called sky wave propagation.
Q3. The special theory of relativity is based on the frame of reference which has constant?
Solution
The special theory of relativity is based on the frame of reference which moves with constant speed
The special theory of relativity is based on the frame of reference which moves with constant speed
Q4. Through which mode of propagation, the radio waves can be sent from one place to another
Solution
The radio waves can be sent from one place to another through following propagation mode. (i) space wave propagation, sky wave propagation and ground wave propagation
The radio waves can be sent from one place to another through following propagation mode. (i) space wave propagation, sky wave propagation and ground wave propagation
Q5.Optical fiber communication is generally preferred over general communication system because
Solution
An optical fibre is move efficient, has signal security and cannnot be grounded as easily as radiowaves
An optical fibre is move efficient, has signal security and cannnot be grounded as easily as radiowaves
Q6. In space communication, the sound waves can be sent from one place to another
Solution
In space communication, the sound waves can be sent from one place to another by superimposing it on undamped electromagnetic waves
In space communication, the sound waves can be sent from one place to another by superimposing it on undamped electromagnetic waves
Q7.A TV tower has a height of 150 m. The area of the region covered, the TV broadcast is (radius of earth=6.4×106m)
Solution
Area of region covered =Ï€d2=Ï€(2hR) =Ï€×2×150×6.4×106 =1.92 Ï€×109 m2=1.92 Ï€×103 km2
Area of region covered =Ï€d2=Ï€(2hR) =Ï€×2×150×6.4×106 =1.92 Ï€×109 m2=1.92 Ï€×103 km2
Q8.The maximum line-of-sight distance dM between two antennas having heights hT and hR above the earth is
Solution
√(2RhT )+√(2RhR )
√(2RhT )+√(2RhR )
Q9.For sky wave propagation of 10 MHz signal, what should be the minimum electron density in ionosphere?
Solution
Area (A) covered by TV signal is given by A=Ï€d2 Where d is range given by d=√2Rh Where Ris radius of earth and h the height of antenna. ∴A=Ï€(2Rh) Given, A1=A,A2=2A ∴A1/A2 =h1/h2 ⇒ h1/h2 =1/2 ⇒h2=2h1 Hence, height of transmitting antenna will have to be doubled.
Area (A) covered by TV signal is given by A=Ï€d2 Where d is range given by d=√2Rh Where Ris radius of earth and h the height of antenna. ∴A=Ï€(2Rh) Given, A1=A,A2=2A ∴A1/A2 =h1/h2 ⇒ h1/h2 =1/2 ⇒h2=2h1 Hence, height of transmitting antenna will have to be doubled.
Q10. In frequency modulation
Solution
In frequency modulation the frequency of the modulated wave is the linear function of the amplitude of the modulating wave
In frequency modulation the frequency of the modulated wave is the linear function of the amplitude of the modulating wave