Miscellaneous and specific question of aldehydes and ketones MCQ Advance Level
Dear Readers,
Compared to other sections, Chemistry is considered to be the most scoring section. If prepared thoroughly, chemistry can help students to secure a meritorious position in the exam. These questions are very important in achieving your success in Exams after 12th.
Q1. Acetophenone can be prepared by
I. Oxidation of 1-phenylethanol
II. Reaction of benzaldehyde with methyl magnesium bromide
III. Friedel-Crafts reaction of benzene with acetyl chloride
IV. Distillation of calcium benzoate
I and III
Q2. Ethanedial has which functional groups(s)
Two aldehydic
Q3. Contents of three bottles were found to react
(i) Neither with Fehling’s solution nor with Tollen’s reagent
(ii) Only with Tollen’s reagent but not with Fehling’s solution
(iii) With both Tollen’s reagent and Fehling’s solution
If they contained either ethanal (acetaldehyde) or propanone (acetone) or benzal (benzaldehyde), which bottle contained which
In (i) propanone, in (ii) benzal and in (iii) ethanal
Q4. Reaction of acetaldehyde with HCN followed by hydrolysis gives a compound which shows
Optical isomerism
Q5. Which of the following has the most acidic proton
(CH3CO)3CH
Q6. The most reactive compound towards formation of cyanohydrin on treatment with KCN followed by acidification is
p-Nitrobenzaldehyde
Q7. Which of the following statements regarding chemical properties of acetophenone are wrong
(1) It is reduced to methyl phenyl carbinol by sodium and ethanol
(2) It is oxidised to benzoic acid with acidified
(3) It does not undergo iodoform electrophilic substitution like nitration at meta position
(4) It does not undergo iodoform reaction with iodine and alkali
3 and 4
Q8. Thiols readily condense with aldehydes in presence of dry HCl gas to form
Diethyl methyl mercaptol
Q9. In ketones, the isomerism starts having number of carbon atoms
5
Q10. A carbonyl compound with molecular weight 86, does not reduce Fehling’s solution but forms crystalline bisulphite derivatives and gives iodoform test. The possible compounds can be
2-pentanone and 3-methyl-2-butanone