States of Matter Quiz-7
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Q1. Frenkel defect is found in crystals in which the radius ration is
Solution
(c) Frenkel defect is observed in the crystals in which the radius ratio is low
(c) Frenkel defect is observed in the crystals in which the radius ratio is low
Q2.Avogadro’s number is the number of molecules present at NTP in:
Solution
(c)
Follow Avogadro’s hypothesis.
Q3. In which one of the following does the given amount of chlorine exert the least pressure in a vessel of capacity 1 dm3 at 273 K?
Solution
(a) Ideal gas equation is Vp=nRT When V and T are same, p∝n Thus, when number of moles, i.e.,n is least, it will exert least pressure. (a) n=(wt.)/(mol.wt.)=0.0355/33.5=1×10-3 mol (b) n=0.071/33.5=2×10-3 mol (c) n=(number of molecules )/NA =(6.023×1021)/(6.023×1023 )=0.01 mol (d) n=0.02 mol Thus, 0.0335 g chlorine will exert the least pressure.
(a) Ideal gas equation is Vp=nRT When V and T are same, p∝n Thus, when number of moles, i.e.,n is least, it will exert least pressure. (a) n=(wt.)/(mol.wt.)=0.0355/33.5=1×10-3 mol (b) n=0.071/33.5=2×10-3 mol (c) n=(number of molecules )/NA =(6.023×1021)/(6.023×1023 )=0.01 mol (d) n=0.02 mol Thus, 0.0335 g chlorine will exert the least pressure.
Solution
(b) At constant pressure V∝T, but according to Gay Lussac’s law the pressure of a given mass of a gas is directly proportional to the absolute temperature. Thus, p1<p2
(b) At constant pressure V∝T, but according to Gay Lussac’s law the pressure of a given mass of a gas is directly proportional to the absolute temperature. Thus, p1<p2
Q6. Oxygen gas is collected by downward displacement of water in a jar. The level of water inside the jar is adjusted to the height of water outside the jar. When the adjustment is made, the pressure exerted by the oxygen is:
Solution
(d) Pdry O2+Pwater vapour=Pwet O2
(d) Pdry O2+Pwater vapour=Pwet O2
Q7.If the pressure of N2/H2 mixture in a closed vessel is 100 atmosphere and 20% of the mixture then reacts, the pressure at the same temperature would be:
Solution
(c)
20% mixture produce 10% NH_3
N2+3H2→2NH3
Thus, percentage remains 90%
Q8.A certain gas takes three times as long to effuse out as helium. Its molecular mass will be:
Q9.Volume occupied by molecules of one mole gas at NTP, each having radius of 10-8 cm is:
Solution
(c)
Volume of molecules in one mole
=4×N×V=4×N×4/3 Ï€r3
=4×6.023×1023×4/3×22/7×(10-8)3
=10.09 mL
Q10. At relatively high pressure, van der Waals’ equation reduces to:
Solution
(c)
At high pressure, volume of molecules should not be neglected in comparison to volume of gas. Also experimental studies reveals PV>RT at high P.