ELECTRONICS-QUIZ 14

ELECTRONICS-QUIZ 14

Dear Readers,

As per analysis for previous years, it has been observed that students preparing for NEET find Physics out of all the sections to be complex to handle and the majority of them are not able to comprehend the reason behind it. This problem arises especially because these aspirants appearing for the examination are more inclined to have a keen interest in Biology due to their medical background. Furthermore, sections such as Physics are dominantly based on theories, laws, numerical in comparison to a section of Biology which is more of fact-based, life sciences, and includes substantial explanations. By using the table given below, you easily and directly access to the topics and respective links of MCQs. Moreover, to make learning smooth and efficient, all the questions come with their supportive solutions to make utilization of time even more productive. Students will be covered for all their studies as the topics are available from basics to even the most advanced. .

Q1. The value of current in the following diagram will be

•  Zero
•  10^-2 A
•  10 A
•  0.025 A

Solution
(b) Here p-n junction as forward biased with voltage =5-3=2 V. ∴Current I=2/200=1/100=10^-2 A

Q2.In a p-n junction diode

•  The current in the reverse biased condition is generally very small
•  The current in the reverse biased condition is small but the forward biased current is independent of the bias voltage
•  The reverse biased current is strongly dependent on the applied bias voltage
•  The forward biased current is very small in comparison to reverse biased current

Solution
(a) The forward voltage overcomes the barrier voltage. Due to which the forward current is high but depends upon the forward voltage applied. The reverse voltage supports the barrier voltage, due to which the reverse current is low.

Q3. In depletion layer of unbiased p-n junction

•  Holes are present
•  Electrons are present
•  Only fixed ions are present
•  None of the above

Solution
(c) In the vicinity of the junction, a region is created, which is devoid of free charge carriers and has immobile ions.

Q4. Electronic configuration of germanium is 2, 8, 18 and 4. To make it extrinsic semiconductor small quantity of antimony is added

•  The material obtained will be N-type germanium in which electrons and holes are equal in number
•  The material obtained will be P-type germanium
•  The material obtained will be N-type germanium which has more electrons than holes at room temperature
•  The material obtained will be N-type germanium which has less electrons than holes at room temperature.

Solution
(c) Artimony is a fifth group impurity and is therefore a donor of electrons

Q5.The given truth table is of

•  OR gate
•  AND gate
•  NOT gate
•  None of above

Solution
(c)‘NOT’ gate

Q6. In the circuit shown in figure the maximum output voltage V₀ is

•  0 V
•  5 V
• 10 V
•  5/√2 V

Solution
(b) For the positive half cycle of input the resulting network is shown below ⇒

(V₀ )_max=1/2 (V_i)_max=1/2×10=5 V

Q7.The combination of gates shown below produces

•  AND gate
•  XOR gate
•  NOR gate
•  NAND gate

Solution
(d) 

 

Hence option (d) is correct

Q8.What is the coordination number of sodium ions in the case of sodium chloride structure

•  6
•  8
•  4
•  12

Solution
(a) In NaCl crystal Na⁺ions is surrounded by 6 Cl^- ion, therefore coordination number of Na⁺ is 6

Q9.What is the output of the combination of the gates shown in the figure?

•  
  
  
  
•  
  
  
  
•  
  
  
  
•  
  
  
  

Solution
(a) 

Q10. In silicon when phosphorus is doped ……. is formed

•  p-type semiconductor
•  n-type semiconductor
•  p-n junction
•  None of these

Solution
(b) Phosphorus is pentavalent, so n-type semiconductor is formed.