As per analysis for previous years, it has been observed that students preparing for NEET find Physics out of all the sections to be complex to handle and the majority of them are not able to comprehend the reason behind it. This problem arises especially because these aspirants appearing for the examination are more inclined to have a keen interest in Biology due to their medical background.
Furthermore, sections such as Physics are dominantly based on theories, laws, numerical in comparison to a section of Biology which is more of fact-based, life sciences, and includes substantial explanations. By using the table given below, you easily and directly access to the topics and respective links of MCQs. Moreover, to make learning smooth and efficient, all the questions come with their supportive solutions to make utilization of time even more productive. Students will be covered for all their studies as the topics are available from basics to even the most advanced.
Q1. Positive rays or canal rays are:
Solution
A fact.
A fact.
Q2.The numbers of spectral lines that can be possible when eletrons in 7th shell in the different hydrogen atoms return to the 2nd shell, is
Solution
Number of spectral lines =((n_2-n_1 )(n_2-n_1+1))/2 =((7-2)(7-2+1))/2=15
Number of spectral lines =((n_2-n_1 )(n_2-n_1+1))/2 =((7-2)(7-2+1))/2=15
Q3. The dynamic mass of a photon of wavelength λ is:
Solution
λ=h/mc
λ=h/mc
Q4. Which of the following statement is incorrect?
Solution
Q5.The relationship between the energy E_1 of the radiation with a wavelength 8000â„« and the energy E_2 of the radiation with a wavelength 16000â„« is
Solution
E=hc/λ,h and c for both causes are same so, E_1/E_2 =λ_2/λ_1 =16000/8000 E_1=2E_2
E=hc/λ,h and c for both causes are same so, E_1/E_2 =λ_2/λ_1 =16000/8000 E_1=2E_2
Q6. The species that has same number of electrons as _16 S^32 is:
Solution
Each has 16 electrons.
Each has 16 electrons.
Q7.Transition of electron from n=3 to n=1 level results in:
Solution
Q8.The wavelengths of the radiations emitted when in a H atom, electron falls from infinity to stationary state 1, is:
Solution
The jump of electron from higher level to lower one shows a decrease in energy and thus, equivalent amount of energy is given out as emission spectra. 1/λ=R_H [1/1^2 -1/∞^2 ]
The jump of electron from higher level to lower one shows a decrease in energy and thus, equivalent amount of energy is given out as emission spectra. 1/λ=R_H [1/1^2 -1/∞^2 ]
Q9.The amount of energy required to remove the electron from a Li^(2+) ion in its ground state is how many times greater than the amount of energy required to remove the electron from an H atom in its ground state?
Solution
E_(Li^(2+) )=E_H×Z^2 ∴E_(1Li^(2+) )/E_(1 H) =Z^2=3^2=9
E_(Li^(2+) )=E_H×Z^2 ∴E_(1Li^(2+) )/E_(1 H) =Z^2=3^2=9
Q10. The mass of a photon with wavelength 3.6 â„« is
Solution
We know that, E=mc^2=hc/λ ∴ λ=h/mc or m=h/(λ.c) where, λ=wavelength of photon h=Planck’s constant m=mass of photon c= velocity of light Given, λ=3.6 â„«=3.6×10^(-10) m ∴ m=(6.62×10^(-34))/(3.6×10^(-10)×3×10^8 ) =6.135×10^(-33) kg
We know that, E=mc^2=hc/λ ∴ λ=h/mc or m=h/(λ.c) where, λ=wavelength of photon h=Planck’s constant m=mass of photon c= velocity of light Given, λ=3.6 â„«=3.6×10^(-10) m ∴ m=(6.62×10^(-34))/(3.6×10^(-10)×3×10^8 ) =6.135×10^(-33) kg