The one subject in NEET which is candidates who can easily attain good marks is Chemistry. That's the reason, often, one doesn’t pay notice and choose to compromise it. But if one wants to rank above others, the tip is to be thorough with NEET chemistry concepts. The understanding of reactions and definite basic understanding is what requires major attention in Chemistry but once done it only gets simpler from there. The main focus on the to-do list should be on getting a hang of the NCERT syllabus of NEET chemistry..
Q1. Given that ∆H(r298 K)=-54.07 kJ mol-1 and ∆S(r298 K)°=10 J mol-1 and R=8.314 JK-1 mol-1. The value of log10K for a reaction, A⇌B is:
Solution
b) ∆G°=∆H°-T∆S°
=-54.07-298×10×10-3 =-57.05 kJ
Also, ∆G°=2.303 RT log_10K log10K=(-57.05×103)/(2.303×8.314×298)
b) ∆G°=∆H°-T∆S°
=-54.07-298×10×10-3 =-57.05 kJ
Also, ∆G°=2.303 RT log_10K log10K=(-57.05×103)/(2.303×8.314×298)
Q2.A thermodynamic state function is:
Solution
c) The fact for a quantity referred as state function
c) The fact for a quantity referred as state function
Q3. The work done by a system in an expansion against a constant external pressure is:
Solution
(b) Wirr. For a process at constant pressure =-P∙∆V; note that work is irreversible if expansion is made at constant pressure.
(b) Wirr. For a process at constant pressure =-P∙∆V; note that work is irreversible if expansion is made at constant pressure.
Q4. ∆H for the reaction given below represents,
CO2(g)+H2(g)⟶CO(g)+H2O(g); ∆H=40 kJ:
Solution
(d) Heat changes during any chemical reaction are referred as heat of reaction are referred as heat of reaction for that change.
(d) Heat changes during any chemical reaction are referred as heat of reaction are referred as heat of reaction for that change.
Q5.∆So will be highest for the reaction
Solution
b) Eq.(b) shows largest phase change ie,gas → solid
b) Eq.(b) shows largest phase change ie,gas → solid
Q6. The enthalpy of dissolution of BaCl2(s) and BaCl2∙2H2O(s) are -20.6 and 8.8 kJ per mol
respectively.The enthalpy of hydration for, BaCl2(s)+2H2O→BaCl2∙2H2O(s) is
respectively.The enthalpy of hydration for, BaCl2(s)+2H2O→BaCl2∙2H2O(s) is
Solution
b)
b)
Q7.A thermodynamic quantity is that:
Solution
c) e.g.,U,H,S, etc.
c) e.g.,U,H,S, etc.
Q8.The heat evolved during the combustion of 112 litre of water gas (mixture of equal volume of H2 and CO) is :
H2(g)+1/2 O2(g)→H2O(g); ∆H= -241.8 kJ
CO(g)+1/2 O2(g)→CO2(g); ∆H= -283 kJ
H2(g)+1/2 O2(g)→H2O(g); ∆H= -241.8 kJ
CO(g)+1/2 O2(g)→CO2(g); ∆H= -283 kJ
Solution
(c) ∆H for combustion of 56 litre H2= (- 24.1 × 56)/22.4
∆H for combustion of 56 litre CO=(-263 × 56)/22.4 ∴ Total ∆H= -1312 kJ
(c) ∆H for combustion of 56 litre H2= (- 24.1 × 56)/22.4
∆H for combustion of 56 litre CO=(-263 × 56)/22.4 ∴ Total ∆H= -1312 kJ
Q9. The enthalpy of formation of HI is 30.4 kJ. Which statement is false according to this observation?
Solution
(c) Due to positive ∆H, HI is endothermic compound and unstable.
(c) Due to positive ∆H, HI is endothermic compound and unstable.
Q10. Select the incorrect statement
Solution
(b) Rest all are correct .
(b) Rest all are correct .