redox-and-equivalent-concept-quiz-1

Redox And Equivalent Concept Quiz-1

Dear Readers,

The one subject in NEET which is candidates who can easily attain good marks is Chemistry. That's the reason, often, one doesn’t pay notice and choose to compromise it. But if one wants to rank above others, the tip is to be thorough with NEET chemistry concepts. The understanding of reactions and definite basic understanding is what requires major attention in Chemistry but once done it only gets simpler from there. The main focus on the to-do list should be on getting a hang of the NCERT syllabus of NEET chemistry..

Q1. The oxidation state of chlorine is highest in the compound :

•  Cl₂
•  HCl
•  Cl₂ O
•  Cl₂ O₇

Solution
(d) Cl has +7 ox.no. in Cl₂ O₇.  

Q2.Mole and millimole of reactants react in the ……….as represented by balanced stoichiometric equation.

•  Molar ratio
•  Equal amount
•  Both (a) and (b)
•  None of these

Solution

(a) It is a fact.

Q3. Oxidation number of N in N₃ H is :  

•  -3
•  +3
•  Zero
•  -1/3

Solution
(d) 3 × a+(+1) = 0 ∴a= -1/3

Q4. In C+H₂ O ⟶CO+H₂ ;H₂ O acts as∶

•  Oxidant
•  Reductant
•  Both (a) and (b)
•  None of these

Solution
(a) H₂¹⁺+2e ⟶H₂⁰

Q5.Which statement is incorrect?

•  Oxidation of a substance is followed by reduction of another
•  Reduction of a substance is followed by oxidation of another
•  Oxidation and reduction are complementary reactions
•  It is not necessary that both oxidation and reduction should take place in the same reaction

Solution
  (d) Oxidation-reduction takes place simultaneously.  

Q6. Titre value is the volume of titrant used for a definite amount of unknown reagent at its :

•  Equivalence point
•  End point
•  Neutralization point
•  All of these

Solution
(d) All terms have same meaning.  

Q7.Among the properties given below, the set of properties shown by CN^- ion towards metal species is : 1. Reducing; 2. Oxidizing ; 3. Complexation

•  1,3
•  1,2,3
•  1,2
•  2,3

Solution

(a) CN^- is reducing and complexing agent.

Q8.2 mole of FeSO₄ are oxidized by 'X' mole of KMnO₄ whereas 2 mole of FeC₂ O₄ are oxidized by 'Y’mole of KMnO₄. The ration f 'X' and 'Y' is :

•  1 : 3
•  1 : 2
•  1 : 4
•  1 : 5

Solution
(a) Fe²⁺ ⟶Fe³⁺+e Mn⁷⁺+5e ⟶Mn²⁺

5 mole FeSO₄=1 mole KMnO₄ 

 'X'=2/3 mole Or

 Fe²⁺ ⟶Fe³⁺+e  (C³⁺ )₂ ⟶2C⁴⁺+2e 

 FeC₂ O₄ ⟶Fe³⁺ +2C⁴⁺+3e 

 Mn⁷⁺+5e ⟶Mn²⁺ 

 5 mole FeC₂ O₄ = 3 mole KMnO₄ 

 ∴'Y'=(3 × 2)/5  

Q9.The ox.no. of S in Na₂ S₄ O₆ is :

•  + 2.5
•  +2 and +3 (two S have +2 and other two have +3)
•  +2 and +3 (three S have +2 and one S has +3)
•  +5 and 0 (two S have +5 and the other two S have 0)

Solution

(d) Ox.no. of S in Na₂ S₄ O₆ is no doubt 2.5 but it is average of two values, i.e., (2×(+5)+2 × 0)/4= +5/2

Q10. Oxidation number of Cl in NOClO₄ is :

•  +7
•  -7
•  +5
•  -5

Solution

(a) Calculate ox.no. of Cl in NOCIO₄ by assuming CIO₄^- and NO⁺.