Redox And Equivalent Concept Quiz-9
Dear Readers,
The one subject in NEET which is candidates who can easily attain good marks is Chemistry. That's the reason, often, one doesn’t pay notice and choose to compromise it. But if one wants to rank above others, the tip is to be thorough with NEET chemistry concepts. The understanding of reactions and definite basic understanding is what requires major attention in Chemistry but once done it only gets simpler from there. The main focus on the to-do list should be on getting a hang of the NCERT syllabus of NEET chemistry..
Q1. The oxidation number of N in NH3 is :
Solution
(a) a+3 × (+1)=0 ∴a= -3
(a) a+3 × (+1)=0 ∴a= -3
Q2.A 0.50 M solution of KI reacts with excess of H2 SO4 and KIO3 solutions according to the equation, 6H+ +5I- +IO3- ⟶3I2+3H2 O. Which of the following statements is true?
Solution
(c)
5 mole I- gives 3 mole I2
Q3. In the conversion of Br2 to BrO3-, the oxidation number of Br changes from
Solution
(a) Bromine has zero oxidation state because it is in free state. 0 Br2⟶BrO3- Let the oxidation number of Br in BrO3- is x. x+(-2×3)=-1 x+(-6)= -1 x=+6-1 x=+5 So, oxidation number changes from 0 to +5.
(a) Bromine has zero oxidation state because it is in free state. 0 Br2⟶BrO3- Let the oxidation number of Br in BrO3- is x. x+(-2×3)=-1 x+(-6)= -1 x=+6-1 x=+5 So, oxidation number changes from 0 to +5.
Q4. LiAIH4 is used as :
Solution
(b) H in LiAIH4 has −1 ox.no. and thus, easily oxidized.
(b) H in LiAIH4 has −1 ox.no. and thus, easily oxidized.
Q6. The oxidation number of phosphorus in PO43-,P4 O10 and P2 O74- is :
Solution
(d) Find oxidation number of P in each.
(d) Find oxidation number of P in each.
Q7.In the reaction, VO+Fe2 O3 ⟶FeO+V2 O5. The eq.wt. of V2 O5 is equal to its :
Solution
(c)
2V2+ ⟶V25++6e
Q8.Ozone tails mercury. The reaction is ….of Hg.
Solution
(b) Hg+O3 ⟶HgO+O2
(b) Hg+O3 ⟶HgO+O2
Q9.A student states that heating of limestone is an oxidation process, the reason he gives that an oxide of the metal is produced on heating. Which one is correct?
Solution
Q10. The reaction; H2 S+H2 O2 ⟶2H2 O+S shows :
Solution
(c)
H2 O2 oxidises S2- to S0.