S-Block Quiz-10
Dear Readers,
The one subject in NEET which is candidates who can easily attain good marks is Chemistry. That's the reason, often, one doesn’t pay notice and choose to compromise it. But if one wants to rank above others, the tip is to be thorough with NEET chemistry concepts. The understanding of reactions and definite basic understanding is what requires major attention in Chemistry but once done it only gets simpler from there. The main focus on the to-do list should be on getting a hang of the NCERT syllabus of NEET chemistry..
Q1. H2 O is dipolar whereas BeF2 is not. It is because:
Solution
(d) BeF2 is linear (sp-hybridization), H2 O is angular (sp3-hybridization).
(d) BeF2 is linear (sp-hybridization), H2 O is angular (sp3-hybridization).
Q2.Which one of the following will dissolve in water most readily?
Solution
(c)
All the alkali halides except lithium fluoride are freely soluble in water. I2 (non-polar) is least soluble in water. Group IIA carbonates (BaCO3 ) are insoluble in water. PbI2 is sparingly soluble in cold water but quite soluble in hot water. KF (most polar) is most readily soluble in water.
Q3. Dead burnt is:
Solution
(a) Dead burnt is CaSO4.
(a) Dead burnt is CaSO4.
Q4. Blanc fixe used in paints is:
Solution
(a) Blanc fixe is finely divided BaSO4.
(a) Blanc fixe is finely divided BaSO4.
Q5.The most soluble halide in water is:
Solution
(d) The solubility order: CaF2<CaCl2<CaBr2<CaI2.
(d) The solubility order: CaF2<CaCl2<CaBr2<CaI2.
Q6. The plaster of Paris is:
Solution
(d) It is a fact.
(d) It is a fact.
Q7.Limestone is not used in which of the following manufacturing processes?
Solution
(a)
Lime stone is not used in the extraction of phosphorus from phosphorite [Ca3 (PO4 )2]
Q8.Which gives apple green colour in fireworks?
Solution
(c) Ba imparts green colour to flame.
(c) Ba imparts green colour to flame.
Q9.Which will react with acid and alkalies both i.e., (amphoteric)
Solution
(d)
BeO+2HCl⟶BeCl2+H2 O;
BeO+2NaOH⟶Na2 BeO2+H2 O.
Q10. In the manufacture of sodium hydroxide, byproduct obtained is:
Solution
(b)
Due to anodic reaction as: 2Cl-⟶Cl2+2e.