S-Block Quiz-6
Dear Readers,
The one subject in NEET which is candidates who can easily attain good marks is Chemistry. That's the reason, often, one doesn’t pay notice and choose to compromise it. But if one wants to rank above others, the tip is to be thorough with NEET chemistry concepts. The understanding of reactions and definite basic understanding is what requires major attention in Chemistry but once done it only gets simpler from there. The main focus on the to-do list should be on getting a hang of the NCERT syllabus of NEET chemistry..
Q1. Which of the following has the largest size in aqueous solution?
Solution
(d) The order of the size of hydrated ions of I group metals is,
(d) The order of the size of hydrated ions of I group metals is,
Li+ (aq.)>Na+ (aq.)>K+ (aq.)>Rb+ (aq.)>Cs+ (aq………….)
Q2.The characteristic not related to alkali metal is
Solution
(a)
Alkali metals have low ionisation energy. They posses minimum value of ionisation energy in their period.
Q3. Both Be and Al become passive on reaction with conc. Nitric acid due to:
Solution
(c) Both Be and Al are rendered passive due to the formation of inert, insoluble and imprevious oxide layer on their surface.
(c) Both Be and Al are rendered passive due to the formation of inert, insoluble and imprevious oxide layer on their surface.
Q4. Potassium when heated strongly in oxygen, it forms:
Solution
(b) Li forms Li2 O,Na forms Na2 O2 and rest all alkali metals forms superoxides MO2.
(b) Li forms Li2 O,Na forms Na2 O2 and rest all alkali metals forms superoxides MO2.
Q5.Black ash is:
Solution
(c) Black ash is Na2 CO3+CaS.
(c) Black ash is Na2 CO3+CaS.
Q6. Bleaching powder is obtained by the interaction of chlorine and
Solution
(b) Ca(OH)2+Cl2→ CaOCl2 +H2 O bleaching powder
(b) Ca(OH)2+Cl2→ CaOCl2 +H2 O bleaching powder
Q7.Least abundant metal in IIA group is:
Solution
(c)
Ra is radioactive and thus, decays instantaneously.
Q8.When KCl is heated with conc. H2 SO4 and solid K2 Cr2 O7, we get:
Solution
(a) 4KCl+6H2 SO4+K2 Cr2 O7⟶2CrO2 Cl2+6KHSO4+3H2 O
(a) 4KCl+6H2 SO4+K2 Cr2 O7⟶2CrO2 Cl2+6KHSO4+3H2 O
Q9.A and B are two salts. A with dilute HCl and B with conc. H2 SO4 react to give reddish brown vapours, hence A and B respectively are:
Solution
(d)
NaNO2 gives NO2(brown) with dil. Acids whereas NaBr and NaNO2 both give brown vapours Br2 and NO2 respectively with conc. acids.
Q10. Slaked lime is:
Solution
(c)
White wash in our houses is made by slaked lime, Ca(OH)2.