s-block-quiz-8

S-Block Quiz-8

Dear Readers,

The one subject in NEET which is candidates who can easily attain good marks is Chemistry. That's the reason, often, one doesn’t pay notice and choose to compromise it. But if one wants to rank above others, the tip is to be thorough with NEET chemistry concepts. The understanding of reactions and definite basic understanding is what requires major attention in Chemistry but once done it only gets simpler from there. The main focus on the to-do list should be on getting a hang of the NCERT syllabus of NEET chemistry..

Q1. A sudden large jump between the values of second and third ionization energies of an element would be associated with the electronic configuration:

•  1s²,2s² 2p⁶,3s¹
•  1s²,2s² 2p⁶,3s² 3p¹
•  1s²,2s² 2p⁶,3s² 3p²
•  1s²,2s² 2p⁶,3s²

Solution
(d) Jump in IP is noticed during the change of shell.  

Q2.The alkali metal which acts as a nutrient for plants is:

•  Na
•  K
•  Li
•  Rb

Solution

(b) K is used as fertilizer (NPK) for nutrition of plants.

Q3. Bleaching action of bleaching powder is due to the liberation of 

•  O₂
•  OCl^-
•  Cl₂
•  Cl^-

Solution
(c) Bleaching action of bleaching powder is due to Cl₂, it liberate with dilute acids or even CO₂. CaOCl₂+CO₂ →CaCO₃+Cl₂

Q4. Alkaline earth metal compounds are les soluble in water than corresponding alkali metal compounds because former have:

•  Lower lattice energy
•  Higher I.P.
•  Higher covalent character
•  Lower covalent character

Solution
(c) It is a reason for given fact.

Q5.Tin dissolves in boiling caustic soda solution because of the formation of soluble:

•  Sn(OH)₂
•  Sn(OH)₄
•  Na₂ SnO₃
•  None of these

Solution
  (c) Sn+2NaOH+H₂ O⟶Na₂ SnO₃+2H₂.  

Q6. Bleaching powder is obtained by treating chlorine with

•  CaCO₃
•  Ca(OH)₂
•  CaO
•  None of these

Solution
(b) Bleaching powder is obtained by treating chlorine with slaked lime. 

 Ca(OH)₂      +Cl₂     →    CaOCl₂ +        H₂ O 

 Slaked lime              bleaching powder  

Q7.Milk of magnesia is used as

•  Antichlor
•  Antacid
•  Antiseptic
•  Food preservative

Solution

(b)Antacid

Q8.The element which on burning in air gives peroxide is

•  Lithium
•  Sodium
•  Rubidium
•  Caesium

Solution
(b) Alkali metals on burning in air give monoxide, peroxide or superoxide. 

 Li forms monoxide. 2Li+1/2 O₂ →Li₂ O

 Na form peroxide as well as monoxide. 

 2Na +O₂→Na₂ O_2 2Na+1/2 O₂→Na₂ O 

 K, Rb, and Cs form superoxide. M(=K,Rb,Cs)+O₂ →MO₂  

Q9.Chlorine reacts with 'X' to form bleaching powder. 'X' is

•  Dry slaked lime
•  Sodium hydroxide
•  Acetone
•  Chloral

Solution

(a) Cl₂+Ca(OH)₂ →CaOCl₂+H₂ O Compound 'X' is dry slaked lime.

Q10. Soda lime is

•  NaOH
•  NaOH and CaO
•  CaO
•  Na₂ CO₃

Solution

(b) NaOH+CaO is called soda lime. 3 : 1