Q1. Benzene and toluene form nearly ideal solutions. At 〖25〗^∘ C, the vapour pressure of benzene is 75 torr and that of toluene is 22 torr. The partial vapour pressure of benzene at 〖20〗^∘ C for a solution containing 78 g of benzene and 46 g of toluene in torr is
Solution
Mixture contains 78 g benzene = 1 mole benzene and 46 g toluene = 0.5 mole toluene Total mole of benzene and toluene=1.5 mol Mole fraction of benzene in mixture =1/1.5=2/3 VP of benzene p_b^∘ =75 torr ∴ Partial vapour pressure of benzene = p_b^∘ X_b =75 ×2/3=50 torr
Mixture contains 78 g benzene = 1 mole benzene and 46 g toluene = 0.5 mole toluene Total mole of benzene and toluene=1.5 mol Mole fraction of benzene in mixture =1/1.5=2/3 VP of benzene p_b^∘ =75 torr ∴ Partial vapour pressure of benzene = p_b^∘ X_b =75 ×2/3=50 torr
Q3. Following solutions at the same temperature will be isotonic :
Solution
For isotonic solutions, π_1= π_2(and for non-electrolytes also c_1=c_2).
For isotonic solutions, π_1= π_2(and for non-electrolytes also c_1=c_2).
Q4. Which of the following liquid pair shows a positive deviation from Raoult’s law?
Solution
D
D
Q5. Which of the following is the expression of Raoult’s law?
(p=vapour pressure of pure solvent, p_s=vapour pressure of the solution)
Solution
According to Raoult’s law, for non volatile solute, the relative lowering of vapour pressure of a solution is equal to the mole fraction of the solute (p-p_s)/p=n/(n+N)
According to Raoult’s law, for non volatile solute, the relative lowering of vapour pressure of a solution is equal to the mole fraction of the solute (p-p_s)/p=n/(n+N)
Q6. Which of the following mixture does not show positive deviation from the Raoult’s law?
Q7.Who gave the phase rule?
Solution
Gibbs gave phase rule for heterogeneous systems.
Gibbs gave phase rule for heterogeneous systems.
Q8.The volume of water to added to 100 〖cm〗^3 of 0.5 N H_2 〖SO〗_4 to get decinormal concentration is
Solution
Q9.40% by weight solution will contain how much mass of the solute in 1L solution, density of the solution is 1.2 g/mL?
Solution
Q10. The azeotropic mixture of water (b. pt.100℃) and HCl (b.pt. 85℃) boils at 108.5℃.When this mixture is distilled it is possible to obtain
Solution
Azerotropic mixture has constant boiling mixture, it is not possible to separate the components of azeotropic mixture by boiling
Azerotropic mixture has constant boiling mixture, it is not possible to separate the components of azeotropic mixture by boiling