REDOX AND EQUIVALENT CONCEPT QUIZ-14

REDOX AND EQUIVALENT CONCEPT QUIZ-14

Dear Readers,

The one subject in NEET which is candidates who can easily attain good marks is Chemistry. That's the reason, often, one doesn't pay notice and choose to compromise it. But if one wants to rank above others, the tip is to be thorough with NEET chemistry concepts. The understanding of reactions and definite basic understanding is what requires major attention in Chemistry but once done it only gets simpler from there. The main focus on the to-do list should be on getting a hang of the NCERT syllabus of NEET chemistry. .

Q1. Millimole of a solute in a solution can be given by :

•  M × V_{(in litre)}
•  M × V_{(in mL)}
•  (wt.)/(mol.wt.) × 1000
•  Both (b) and (c)

Solution
Both are same

Q2.Which can act as oxidant?

•  H₂ O₂
•  H₂ S
•  NH₃
•  None of these

Solution
Oxygen of H₂ O₂ gets reduced from − 1 to −2.

Q3.  When an acidified solution of ferrous ammonium sulphate is treated with KMnO₄ solution, the ion which is oxidised is :

•   Fe⁽²⁺⁾
•  SO₄^(2-)
•  NH₄⁺
•  MnO₄^-

Solution
Fe⁽²⁺⁾⟶Fe⁽³⁺⁾+e.

Q4. In which reaction the underlined substance has been reduced?

•  Carbon monoxide + copper oxide ⟶ carbon dioxide + copper
•  Copper oxide + hydrochloric acid ⟶ water + copper chloride
•  Steam + iron ⟶ hydrogen + iron oxide
•  Hydrogen + iron oxide ⟶ water + iron

Solution
H₂⁽¹⁺⁾ O ⟶H₂⁰ ; Steam is reduced.

Q5.Sulphurous acid can be used as :

•  Oxidising agent
•  Reducing agent
•  Bleaching agent
•  All of these

Solution
 S in H₂ SO₃ is in +4 oxidation state. It lies in between its maximum and minimum oxidation state, i.e,+6 and -2 and thus, S can increase or decrease its ox.no.as the case may be.

Q6. Oxalic acid on reacting with acidified KMnO₄ is oxidised to :

•  CO and H₂
•  CO₂and H₂
• CO₂ and H_{2 O}
•  CO and H₂O

Solution
Mn⁽⁷⁺⁾+5e ⟶Mn⁽²⁺⁾ C₂⁽³⁺⁾ ⟶2C⁽⁴⁺⁾+2e

Q7.The oxidation number of Xe in XeF₄ and XeO₂ is

•  +6
•  +4
•  +1
•  +3

Solution
The oxidation state of Xe in both XeO₂ and XeF₄ is 4. XeO₂ XeF₄ x+2(-2)=0 x+4(-1)=0 x=4 x=4

Q8.When NaCl is dissolved in water, the sodium ion becomes :

•  Oxidized
•  TReduced
•  Hydrolsed
•  hydrated

Solution
Ions are hydrated on dissolution of salt in water.

Q9.Which change requires a reducing agent?

•  CrO₄^(2-) ⟶CrO₇^(2-)
•  BrO₃^- ⟶BrO^-
•  H₂ O₂ ⟶O₂
•  Al(OH)₃ ⟶Al(OH)₄^-

Solution
4e+Br⁽⁵⁺⁾⟶Br⁽¹⁺⁾ ; Thus, BrO₃^- is to be reduced by a reducing agent.

Q10. Oxidation state of oxygen is −1 in the compound :

•  NO₂
•  MnO₂
•  PbO₂
• Na₂ O₂

Solution
Na₂ O₂ is sodium peroxide.