JEE Advanced is a high level exam that checks your concept by putting various types of questions. The questions are in a different format from JEE mains, herein the questions are : single correct multiple choice questions, multiple correct multiple choice questions, statement based questions and comprehension type questions..
Q1.
[Ni(CN)4 ]2- and [Ni(CO)4]have
[Ni(CN)4 ]2- and [Ni(CO)4]have
Solution
(c)
[Ni(CN)_4 ]^(2-) ∶ dsp^2 square planar
Ni(CO)_4 ∶ sp^3 tetrahedral
(c)
[Ni(CN)_4 ]^(2-) ∶ dsp^2 square planar
Ni(CO)_4 ∶ sp^3 tetrahedral
Q2.
A complex can be formally formed from K2 [PtCl4] by which one of the following sequences of substitution of the chloride ions?
A complex can be formally formed from K2 [PtCl4] by which one of the following sequences of substitution of the chloride ions?
Solution
(d)
Ligand strength is in order
Py
Thus, replacement of Cl^- ligands by above ligands is in same order
(d)
Ligand strength is in order
Py
Thus, replacement of Cl^- ligands by above ligands is in same order
Q3. Consider the following complexes:
I. K2 PtCl6 II.PtCl4∙2NH3 III.PtCl4∙3NH3 IV.PtCl4∙5NH3
Their electrical conductances in aqueous solutions are
I. K2 PtCl6 II.PtCl4∙2NH3 III.PtCl4∙3NH3 IV.PtCl4∙5NH3
Their electrical conductances in aqueous solutions are
Solution
(a)
(a)
Q4. Of the following complex ions, the one that probably has the largest overall formation constant, K_f, is
Solution
(d) [Co(en)_3 ]^(3+)is most stable due to chelate formation Thus, highest K_f value
(d) [Co(en)_3 ]^(3+)is most stable due to chelate formation Thus, highest K_f value
Q5.Which of the following complex species is not expected to exhibit optical isomerism?
Solution
(b) It does not lack symmetry
(b) It does not lack symmetry
Q6. The ions or molecules attached to the central metal atom or ion in a complex are called
Solution
(a)
(a)
Q7.
[Co(NH3 )5 (NO2 )]2+and[Co(NH3 )5(ONO)]2+will differ in
[Co(NH3 )5 (NO2 )]2+and[Co(NH3 )5(ONO)]2+will differ in
Solution
(a) Due to different n linkage, of NO_2(metal linked to Co) and ONO (metal linked to Co) they differ in colour
(a) Due to different n linkage, of NO_2(metal linked to Co) and ONO (metal linked to Co) they differ in colour
Q8.Potassium diamminedicyanosulphatosuperoxo palatinate (IV) is
Solution
(a)
(a)
Q9.Arrange the following in order of decreasing number of unpaired electrons
I. [Fe(H_2 O)_6 ]^(2+)II. [Fe(CB)_6 ]^(3-)
III. [Fe(CN)_6 ]^(4-)IV. [Fe(Fe(H_2 O)_6 ]^(3+ )
I. [Fe(H_2 O)_6 ]^(2+)II. [Fe(CB)_6 ]^(3-)
III. [Fe(CN)_6 ]^(4-)IV. [Fe(Fe(H_2 O)_6 ]^(3+ )
Solution
(a)
(a)
Q10. Among the following metal carbonyls, C—O bond order is lowest in
Solution
(b) Thus, (I) and (IV) are correct
(b) Thus, (I) and (IV) are correct