JEE Advanced is a high level exam that checks your concept by putting various types of questions. The questions are in a different format from JEE mains, herein the questions are : single correct multiple choice questions, multiple correct multiple choice questions, statement based questions and comprehension type questions..
Q1.
Coordination number of calcium is six in
Coordination number of calcium is six in
Solution
(a) EDTA is hexadentate
(a) EDTA is hexadentate
Q2.
Which has aromatic ring in complex
Which has aromatic ring in complex
Solution
(b)
(b)
Q3. If ∆_0 and ∆_t represent crystal field splitting energies for d-orbitals for octahedral and tetrahedral geometries respectively, then for d^6 (high spin in both cases) what are CFSE (ignore the pairing energy) respectively?
Solution
(c)
(c)
Q4. Total number of geometrical isomers for the complex [RhCl(CO)(PPh_3)(NH_2)] is
Solution
(c) [M (abcd)] complex is square planar so will have three geometrical isomers.
(c) [M (abcd)] complex is square planar so will have three geometrical isomers.
Q5.Spin only magnetic moment of the compound Hg[Co(SCN)_4]is
Solution
(b)
(b)
Q6. Of the following complex ions, one is a Bronsted-Lowry acid That one is
Solution
(c)
(c)
Q7.Select the correct statement
Solution
(c) Cl^- is a weak ligand hence [MoCl_6 ]^(3-) 〖sp〗^3 d^2hybridisation and with unpaired electrons is paramagnetic (en) is a strong ligand hence [Co(en)_3 ]^(3+)-d^2 sp^3 hybridization and with all paired electrons is diamagnetic
(c) Cl^- is a weak ligand hence [MoCl_6 ]^(3-) 〖sp〗^3 d^2hybridisation and with unpaired electrons is paramagnetic (en) is a strong ligand hence [Co(en)_3 ]^(3+)-d^2 sp^3 hybridization and with all paired electrons is diamagnetic
Q8.[Cr(NH_3 )_5 Br)Cl and [Cr(NH_3 )_5 Cl]Brcan be distinguished by / and isomerism shown is
Solution
(b) Complexes differ in nature of lonisation
(b) Complexes differ in nature of lonisation
Q9.In the complex [CoCl_3∙4NH_3]
Solution
(c)
(c)
Q10. The pair of compounds having metals in their highest oxidation state is
Solution
(b)
(a) In MnO_2,FeCl_3oxidation states of Mn and Fe are +4 and +3 respectively.
(b) In 〖(MnO_4)〗^-,CrO_2 Cl_2 oxidation states of Mn and Cr are +7 and +6 respectively.
(c) In [Fe(CN)_6 ]^(3-) ,[Co(CN)_3] oxidation states of Fe and Co are +3 and +3 respectively.
(d) [NiCl_4 ]^(2-) ,[CoCl_4 ]^- oxidation states of Ni and Co are +2 and +3 respectively.
(b)
(a) In MnO_2,FeCl_3oxidation states of Mn and Fe are +4 and +3 respectively.
(b) In 〖(MnO_4)〗^-,CrO_2 Cl_2 oxidation states of Mn and Cr are +7 and +6 respectively.
(c) In [Fe(CN)_6 ]^(3-) ,[Co(CN)_3] oxidation states of Fe and Co are +3 and +3 respectively.
(d) [NiCl_4 ]^(2-) ,[CoCl_4 ]^- oxidation states of Ni and Co are +2 and +3 respectively.