JEE Advanced is a high level exam that checks your concept by putting various types of questions. The questions are in a different format from JEE mains, herein the questions are : single correct multiple choice questions, multiple correct multiple choice questions, statement based questions and comprehension type questions..
Q1.
Select the correct statement
Select the correct statement
Solution
(c)
(c)
Q2.
IUPAC name of is K_4 [Fe(CN)_6 ] is
IUPAC name of is K_4 [Fe(CN)_6 ] is
Solution
(d)
+2
↓
K_4 [Fe(CN)_6]
Cation anion
(d)
+2
↓
K_4 [Fe(CN)_6]
Cation anion
Q3. Among Ni(CO)_4∙[Ni(CN)_4 ]^(2-) and NiCl_4^(2-)
Solution
(a)
Ni(CO)_4 sp^3 diamagnetic
[Ni(CN)_4 ]^(2-) dsp^2 diamagnetic
[NiCl_4 ]^(2-) sp^3 paramagnetic
(a)
Ni(CO)_4 sp^3 diamagnetic
[Ni(CN)_4 ]^(2-) dsp^2 diamagnetic
[NiCl_4 ]^(2-) sp^3 paramagnetic
Q4. Cu^(2+ ) and Cd^(2+)are distinguished through formation of complex [Cu(CN)_4 ]^(3-) and [Cs(CN)_4 ]^(2-) , when H_2 S gas is passed
Solution
(a)
[Cu(CN)_4 ]^(3-) is stable, does not ionize
[Cd(CN)_4 ]^(2-) is unstable, ionizes to form Cd^(2+), thus CdS is precipitated
(a)
[Cu(CN)_4 ]^(3-) is stable, does not ionize
[Cd(CN)_4 ]^(2-) is unstable, ionizes to form Cd^(2+), thus CdS is precipitated
Q5.Which one of the following complex species does not obey the EAN rule?
Solution
(b) EAN rule is not followed in which EAN of metal ≠ EC of nearest inert gas
(b) EAN rule is not followed in which EAN of metal ≠ EC of nearest inert gas
Q6. Zeisse’s salt is
Solution
(b)
(b)
Q7.[Co(NO_2 ) (NH_3 )_5 ]^(2+) is yellow in colour, then its linkage isomer is
Solution
(b)
(b)
Q8.Select the correct statement
Solution
(c)
(c)
Q9.[Fe^(II ) (O_2 ) (CN)_4 Cl]^(4- )is named as
Solution
(c)
[Fe(O_2 ) (CN)_4 (Cl)]^(4-)
↑ ↓ ↓ ↓
+2 2x -4 -1 =-4
Thus, oxygen is as superoxo
(c)
[Fe(O_2 ) (CN)_4 (Cl)]^(4-)
↑ ↓ ↓ ↓
+2 2x -4 -1 =-4
Thus, oxygen is as superoxo
Q10. When concentrated HClis added to a, solution of [Co(H_2 O)_6 ]^(2+) ion, an intense blue colour develops due to the formation which one of the following
Solution
(a)
[Co(H_2 O)_6 ]^(2+)+6Cl^-→[CoCl_6 ]^(4+)+6H_2 O
Cl^- replaces H_2 Oligands and intense blue colour is developed
(a)
[Co(H_2 O)_6 ]^(2+)+6Cl^-→[CoCl_6 ]^(4+)+6H_2 O
Cl^- replaces H_2 Oligands and intense blue colour is developed