Chemistry Aptitude Quiz
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IIT JEE exam which consists of JEE Main and JEE Advanced is one of the most important entrance exams for engineering aspirants. The exam is held for candidates who are aspiring to pursue a career in the field of engineering and technical studies.
Chemistry is important because everything you do is chemistry! Even your body is made of chemicals. Chemical reactions occur when you breathe, eat, or just sit there reading. All matter is made of chemicals, so the importance of chemistry is that it's the study of everything..
Q1. Statement 1: The pK_a value of (I) is lower than the pK_a value of (II)
Statement 2: Nonaromatic compounds are more stable than anti-aromatic compounds
Statement 2: Nonaromatic compounds are more stable than anti-aromatic compounds
Solution
Q2.
Solution
Q3. Statement 1: The order of stability of carbocation are
Statement 2: The stability of carbocations is influenced by both resonance and inductive effects
Statement 2: The stability of carbocations is influenced by both resonance and inductive effects
Solution
(c) The stability of carbocation is explained on the basis of hyperconjugation and inductive effect hence the stability order of carbocation is 3°>2°>1°>Methyl carbocation
(c) The stability of carbocation is explained on the basis of hyperconjugation and inductive effect hence the stability order of carbocation is 3°>2°>1°>Methyl carbocation
Q4. Statement 1: All the C atoms of but-2-ene lie in one plane
Statement 2: Double-bond C atoms are sp^2 hybridised
Statement 2: Double-bond C atoms are sp^2 hybridised
Solution
Q5.Statement 1: Both cis-1, 3-dimethyl cyclobutane and trans-1,3-dimethyl cyclobutane are optically inactive
Statement 2: cis-1,3-Dimethyl cyclobutane has the plane of symmetry, whereas trans form has the centre of symmetry
Statement 2: cis-1,3-Dimethyl cyclobutane has the plane of symmetry, whereas trans form has the centre of symmetry
Solution
Part
Part
Q6.
Statement 1: p-methyl benzyl carbocation (I) is more stable than benzyl carbocation (II)
Statement 2: Heterovalent or no bond resonance
Statement 2: Heterovalent or no bond resonance
Solution
Q7.Statement 1: Benzene (boiling point353 K) and methanol (boiling point338 K) are separated by simple distillation
Statement 2: Fractional distillation is used to separate two liquids from their mixture when their boiling points differ by 20° or so
Statement 2: Fractional distillation is used to separate two liquids from their mixture when their boiling points differ by 20° or so
Solution
(c)
(A) is correct. Simple distillation is used to separate two liquids which differ in their boiling points widely. (R) is incorrect because fractional distillation is used to separate the two liquids which differ in their boiling points by 10℃ or so
(c)
(A) is correct. Simple distillation is used to separate two liquids which differ in their boiling points widely. (R) is incorrect because fractional distillation is used to separate the two liquids which differ in their boiling points by 10℃ or so
Q8. Statement 1: Normally and molarity can be calculated from each other.
Statement 2: Normally is equal to the product of molarity and n.
Statement 2: Normally is equal to the product of molarity and n.
Solution
(a)
Normality =molarity×n (n =mol wt. of solute /eq. wt. of solute)
(a)
Normality =molarity×n (n =mol wt. of solute /eq. wt. of solute)
Q9.
Solution
Part
Part
Q10. Statement 1: Dumas method is more applicable to nitrogen containing organic compounds than Kjeldahl's method.
Statement 2: Kjeldahl's method does not give satisfactory results for compounds in which N is linked to O atom
Statement 2: Kjeldahl's method does not give satisfactory results for compounds in which N is linked to O atom
Solution
(b)
Both (A) and (R) are correct, but (R) is not the correct explanation for (A)
(b)
Both (A) and (R) are correct, but (R) is not the correct explanation for (A)
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