REDOX REACTIONS Quiz-1

Chemistry Aptitude Quiz

Dear Readers,

IIT JEE exam which consists of JEE Main and JEE Advanced is one of the most important entrance exams for engineering aspirants. The exam is held for candidates who are aspiring to pursue a career in the field of engineering and technical studies. Chemistry is important because everything you do is chemistry! Even your body is made of chemicals. Chemical reactions occur when you breathe, eat, or just sit there reading. All matter is made of chemicals, so the importance of chemistry is that it's the study of everything..

Q1. The reagent with which both acetaldehyde and acetone react easily is:

•  Tollens reagent
•  Schiffs regent
•  Grignard reagent
•  Fehling’s solution

Solution

Q2.

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Solution

Q3.  A metal ionM^(3+) loses three electrons; its oxidation number will be

•  +3
•  +6
•  0
•  -3

Solution
(b)
M^(3+)⟶M^(6+)+3e^-

Q4.  

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Solution

(c) The reduction of ArNO_2 group under basic condition with (Zn dust + NaOH) gives hydrazobenzene compound. So the answer is (c)

Q5.

•  a=2,b=4,c=6 and x=2,y=6,z=3
•  a=4,b=2,c=6 and x=6,y=2,z=3
•  a=6,b=4,c=2 and x=6,y=3,z=2
•  a=1,b=4,c=6 and x=2,y=6,z=3

Solution
 

Q6. 

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Solution

Q7.Which of the following is a redox reaction?

•  NaCl+KNO_3⟶NaNO_3+KCl
•  CaC_2 O_4+2HCl⟶CaCl_2+H_2 C_2 O_4
•  Mg(OH)_2+2NH_4 Cl⟶MgCl_2+2NH_4 OH
•  Zn+2AgCN⟶2Ag+Zn(CN)_2

Solution
(d)
Zn⟶Zn^(2+)+2e^-
Ag^⊕+e^-⟶Ag
In (a),(b) and (c), oxidation number does not change

Q8.When copper is treated with a certain concentration of nitric acid, nitric oxide and nitrogen dioxide are liberated in equal volumes according to the equation
xCu+yHNO_3⟶Cu(NO_3 )_2+NO+NO_2+H_2 O
The coefficients x and y are

•  2 and 3
•  2 and 6
•  1 and 3
•  3 and 8

Solution

Q9.For the redox reaction
xMnO_4^( ⊖)+yC_2 O_4^( 2-)+zH^⊕⟶ Mn^(2+)+CO_2+H_2 O
the coefficients x,y, and z are

•  2,5,16
•  16,5,2
•  5,16,2
•  2,16,5

Solution
(a) Balanced equation is 2MnO_4^( ⊖)+5C_2 O_4^(2-)+16H^⊕⟶2Mn^(+2)+10CO_2+8H_2 O ∴x.y and z are 2,5,16

Q10. The number of moles of KMnO_4requried to oxidize 1 mol of Fe(C_2 O_4) in acidic medium is

•  0.6
•  1.67
•  0.2
• 0.4

Solution
(a)
Equivalent of MnO_4^⊖= Equivalent ofFe (C_2 O_4 )
(n=5) (n=3)

Written by: AUTHORNAME

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