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Chemistry is important because everything you do is chemistry! Even your body is made of chemicals. Chemical reactions occur when you breathe, eat, or just sit there reading. All matter is made of chemicals, so the importance of chemistry is that it's the study of everything..
Q1. The oxidation number P inBa(H_2 PO_2 )_2is
Solution
(a) Ba^(2+) (H_2 PO_2 )_2^(-1×2) ∴H_2 PO_2^( ⊖)=2+x-4=-1 ∴x=+1 Oxidation state of P=+1
(a) Ba^(2+) (H_2 PO_2 )_2^(-1×2) ∴H_2 PO_2^( ⊖)=2+x-4=-1 ∴x=+1 Oxidation state of P=+1
Q2.In which of the following processes is nitrogen oxidised?
Solution
(a) NH_4^( ⊕)⟶N_2 Oxidation state of N=-3 Oxidation state of N=0 In the other reaction, the oxidation state of N decreases
(a) NH_4^( ⊕)⟶N_2 Oxidation state of N=-3 Oxidation state of N=0 In the other reaction, the oxidation state of N decreases
Q3. Which of the following is an intermolecular redox reaction?
Solution
(d) Intermolecular redox reaction involves oxidation of one molecule and reduction of the other molecule like in redox reactions
(d) Intermolecular redox reaction involves oxidation of one molecule and reduction of the other molecule like in redox reactions
Q4.
Solution
(b) Lemieux reagent (KMnO_4+ NaIO_4) converts RCH= to RCOOH and R_2 C = to R_2 C=O, while with (OsO_4+NaIO_4) converts to RCHO and R_2 C= to R_2 C=O group. So the answer is (b)
(b) Lemieux reagent (KMnO_4+ NaIO_4) converts RCH= to RCOOH and R_2 C = to R_2 C=O, while with (OsO_4+NaIO_4) converts to RCHO and R_2 C= to R_2 C=O group. So the answer is (b)
Q5.The compound that will not give iodoform on treatment with alkali and iodine is:
Solution
Q6. A mole of N_2 H_4 loses 10 mol of electrons to form a new compound Y. Assuming that all the nitrogen appears in the new compound, what is the oxidation state of nitrogen in Y? (There is no change in the oxidation number of hydrogen)
Solution
Q7.
Solution
Q8.Which of the following is the best description of the behavior of bromine in the reaction given below?
H_2 O+Br_2⟶HOBr+HBr
Solution
(b) It is a disproportionation reaction
(b) It is a disproportionation reaction
Q9.The oxidation state of A, B and C in a compound are +2, +5, and -2 respectively. The compound is
Solution
Q10. Hydrogenation of benzoyl chloride in the presence of Pd on BaSO_4gives:
Solution
Part B
Part B