SOLUTIONS Quiz-9

Solutions Quiz-9

Dear Readers,

IIT JEE exam which consists of JEE Main and JEE Advanced is one of the most important entrance exams for engineering aspirants. The exam is held for candidates who are aspiring to pursue a career in the field of engineering and technical studies. Chemistry is important because everything you do is chemistry! Even your body is made of chemicals. Chemical reactions occur when you breathe, eat, or just sit there reading. All matter is made of chemicals, so the importance of chemistry is that it's the study of everything..

Q1. The value of K_f for water is 1.86°, calculated from glucose solution. The value of K_f for water calculated for NaCl solution will be

•  =1.86
•  < 1.86
•  > 1.86
•  Zero

Solution

Q2.Which of the following solutions (1 molal) will have the maximum freezing point, assuming equal ionization in each case?

•  [Fe(H₂ O)₆ ] Cl₃
•  [Fe(H₂ O)₅ Cl] Cl₂.H₂ O
•  [Fe(H₂ O)₄ Cl₂ ] Cl∙2H₂ O
•  [Fe(H₂ O)₃ Cl₃ ]∙3H₂ O

Q3.  The mole fraction of toluene in the vapour phase which is in equilibrium with a solution of benzene (P_B°=120 torr) and toluene (P_T°=80 torr) having 2.0 mol of each is

•  0.50
•  0.25
•  0.60
•  0.40

Solution

Q4. When common salt is dissolved in water

•  The melting point of the solution increases
•  The boiling point of solution decreases
•  Both melting point and boiling point decrease
•  The boiling point of the solution increases

Solution

Q5.What will be the molecular weight of NaCl determined experimentally following elevation in the boiling point or depression in freezing point method?

•  < 58.5
•  > 58.5
•  =58.5
•  None

Solution

Q6. 0.004 M Na₂ SO₄ is isotonic with 0.01 M glucose. Degree of dissociation of Na₂ SO₄ is

•  75%
•  50%
• 25%
•  85%

Solution

Q7.The molecular weight of benzoic acid in benzene as determined by depression in the freezing point method corresponds to

•  Ionization of benzoic acid
•  Dimerization of benzoic acid
•  Trimerization of benzoic acid
•  Solvation of benzoic acid

Solution

Q8.PtCl₄.6H₂ O can exist as a hydrated complex; 1 m aqueous solution has the depression in freezing point of 3.72°. Assume 100% ionization and K_f (H₂ O)=1.86° mol^(-1) kg, then the complex is

•  [Pt(H₂ O)₆ ] Cl₄
•  [Pt(H₂ O)₄ Cl₂ ] Cl₂∙2H₂ O
•  [Pt(H₂ O)₃ Cl₃ ] Cl∙3H₂ O
•  [Pt(H₂ O)₂ Cl₄ ]∙4H₂ O

Solution

Q9.The molal depression constant for water in 1.86℃. The freezing point of a 0.05-molal solution of a non electrolyte in water is

•  -1.86℃
•  -0.93℃
•  -0.093℃
•  0.93℃

Solution

Q10. Which of the following will have the highest boiling point at 1 atm pressure?

•  0.1 M NaCl
•  0.1 M sucrose
•  0.1 M BaCl₂
• 0.1 M glucose

Solution

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