SOME BASIC CONCEPTS OF CHEMISTRY Quiz-28

Some basic concepts of chemistry Quiz-28

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IIT JEE exam which consists of JEE Main and JEE Advanced is one of the most important entrance exams for engineering aspirants. The exam is held for candidates who are aspiring to pursue a career in the field of engineering and technical studies. Chemistry is important because everything you do is chemistry! Even your body is made of chemicals. Chemical reactions occur when you breathe, eat, or just sit there reading. All matter is made of chemicals, so the importance of chemistry is that it's the study of everything..

Q1.Fe^(2+) does not give blue colour with K_4 [Fe(CN)_6] but on its reaction with (X), blue colour appears, (X) can be

•  MnO_4^-/H^+
•  H_2 SO_4
•  NH_3
•  HCl

Solution

Q2.20 mL of x M HCl neutralizes 5 mL of 0.2 M Na_2 CO_3 solution to phenolphthalein end-point. The value of x is

•  0.167 M
•  0.133 M
•  0.150 M
•  0.05 M

Solution

Q3. 

•  NaCl
•  NH_4 Cl
•  NH_4 NO_2
•  NH_4 NO_3

Solution

Q4. CuSO_4 is decolourised on addition of KCN, the product is

•  [Cu(CN)_4 ]^(2-)
•  [Cu(CN)_4 ]^(3-)
•  Cu(CN)_2
•  CuCN

Solution

Q5. An excess of NaOH was added to 100 mL of a FeCl_3 solution which gives 2.14 of Fe(OH)_3. Calculate the normality of FeCl_3 solution

•  0.2 N
•  0.3 N
•  0.6 N
•  1.8 N

Solution
 

Q6. A mixture is known to contain NO_3^- and NO_2^-. Before performing ring test for NO_3^-, the aqueous solution should be made free of NO_2^-. This is done by heating aqueous extract with

•  Conc. HNO_3
•  dil.HNO_3
• Urea
•  Zinc dust

Solution

Q7. If 0.50 mol of BaCl_2 is mixed with 0.20 mol of Na_3 PO_4, the maximum number of moles of Ba_3 (PO_4 )_2 that can be formed is

•  0.70
•  0.50
•  0.20
•  0.10

Solution

Q8. A bottle which contains 200 mL of 0.1 M NaOH solution, absorbs 1.00 millimol of CO_2 from the air. This solution is titrated with standard HCl solution using phenolphthalein indicator. Normality of resulting solution is found as

•  0.190 N
•  0.380 N
•  0.095 N
•  0.0475 N

Solution

Q9. In the following final result is …0.1 mole 〖 CH〗_4+3.01×10^23 molecules CH_4-9.6 g CH_4=x mole H atoms

•  0 mol H atom
•  0.2 mol H atom
•  0.3 mol H atom
•  0.4 mol H atom

Solution

Q10. The largest number of molecules is in

•  36 g of water
•  28 g of carbon monoxide
•  46 g of ethyl alcohol
• 54 g of nitrogen pentoxide

Solution