SOME BASIC CONCEPTS OF CHEMISTRY Quiz-38

Some basic concepts of chemistry Quiz-38

Dear Readers,

IIT JEE exam which consists of JEE Main and JEE Advanced is one of the most important entrance exams for engineering aspirants. The exam is held for candidates who are aspiring to pursue a career in the field of engineering and technical studies. Chemistry is important because everything you do is chemistry! Even your body is made of chemicals. Chemical reactions occur when you breathe, eat, or just sit there reading. All matter is made of chemicals, so the importance of chemistry is that it's the study of everything..

Q1. _17^35 Cl and _17^37 Cl are two isotopes of chlorine. If average atomic mass is 35.5 then ration of these two isotopes is

•  35 : 37
•  1 : 3
•  3 : 1
•  2 : 1

Solution

Q2.1 mole BaF_2 is treated with 2 moles of H_2 SO_4.To make the resulting mixture neutral, NaOH is added. NaOH required in this process is

•  4 mol NaOH
•  2 mol NaOH
•  3 mol NaOH
•  1 mol NaOH

Solution

Q3. A certain compound has the molecular formula X_4 O_6. If 10 g of X_4 O_6 has 5.72 g X, the atomic mass of X is

•  32 amu
•  37 amu
•  42 amu
•  98 amu

Solution

Q4. Select the correct statement(s)

•  Ag_2 S_2 O_3 appears as white precipitate when Na_2 S_2 O_3 reacts with AgNO_3
•  Ag_2 S_2 O_3 is unstable turning black on standing due to formation of Ag_2 S
•  S_2 O_3^(2-) can form soluble complex [Ag(S_2 O_3 )_2 ]^(3-) with Ag^+
•  All of the above are correct statements

Solution

Q5. M^(2+) ion is isoelectronic of SO_2 and has (Z+2) neutrons (Z is atomic number of M) Thus, ionic mass of M^(2+) is

•  70
•  66
•  68
•  64

Solution
 

Q6. 10 g of CaCO_3 contains

•  10 moles of CaCO_3
•  0.1 g atom of Ca
• 6×10^23 atoms of Ca
•  0.1 of equivalent of Ca

Solution

Q7. Turnbull’s blue and Prussian’s blue respectively are

•  I, II
•  I, III
•  III, IV
•  IV, III

Solution

Q8. A compound with molecular mass 180 is acylated with CH_3 COCl to get a compound with molecular mass 390. The number of amino groups present per molecule of the former compound is

•  2
•  5
•  4
•  6

Solution

Q9. 0.31 g of N-containing compound on reaction with NaOH gave NH_3 which required 100 mL of 0.1 N HCl.Hence, % of N is

•  45.16%
•  90.32%
•  22.58%
•  11.29%

Solution

Q10. An aqueous solution of NaCl is 5.85%. The volume in which 1 mole of it is dissolved will be

•  1 L
•  10 L
•  5.85 L
• 58.5 L

Solution