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Chemistry is important because everything you do is chemistry! Even your body is made of chemicals. Chemical reactions occur when you breathe, eat, or just sit there reading. All matter is made of chemicals, so the importance of chemistry is that it's the study of everything..
Q1. The total spin and magnetic moment for the atom with atomic number 24 are:
Solution
(a)
Atomic number =24
Structure is 3d^5,4s^1,n=6
Total spin = ±1/2×6=±3
Magnetic moment = √(n(n+2))=√(6(6+2))=√48 BM
(a)
Atomic number =24
Structure is 3d^5,4s^1,n=6
Total spin = ±1/2×6=±3
Magnetic moment = √(n(n+2))=√(6(6+2))=√48 BM
Q2.For two different disintegration half-lives are equal at equilibrium. This is only when
Solution
(d)
〖N_1 λ_1=N_2 λ〗_2at equilibrium
N_1/t_1 =N_2/t_2 t_1and t_2 are half-lives
If t_1=t_2then N_1=N_2
If λ_1=λ_2then N_1=N_2
Since, T_75=2T_50
Hence, if (T_75 )_1=(T_75 )_2
Then N_1=N_2
(d)
〖N_1 λ_1=N_2 λ〗_2at equilibrium
N_1/t_1 =N_2/t_2 t_1and t_2 are half-lives
If t_1=t_2then N_1=N_2
If λ_1=λ_2then N_1=N_2
Since, T_75=2T_50
Hence, if (T_75 )_1=(T_75 )_2
Then N_1=N_2
Q3. Bohr’s model of atom is not in agreement with
Solution
Part D
Part D
Q4. The correct ground state electronic configuration of chromium atom is
Solution
Part A
Part A
Q5.
Solution
Part A opt-right
Part A opt-right
Q6. When two electrons are placed in two degenerate orbitals of the atom, the energy is lower if their spin is parallel. The statement is based upon
Solution
(c)
Hund’s rule
(c)
Hund’s rule
Q7.At two stages of disintegration, disintegration constants are respectively 1×10^(-2) s^(-1) and 1×10^(-5) s^(-1).At first stage 2000 atoms are disintegrating. At second stage number of atoms disintegrating would be
Solution
(b)
For disintegration
N_1 λ_1=N_2 λ_2
N_2=λ_1/λ_2 N_1=(1×10^(-2))/(1×0^(-5) )×200
=2×10^6
(b)
For disintegration
N_1 λ_1=N_2 λ_2
N_2=λ_1/λ_2 N_1=(1×10^(-2))/(1×0^(-5) )×200
=2×10^6
Q8.The correct set of quantum numbers for the unpaired electron of chlorine atom is:
nIm_l
Solution
Part C
Part C
Q9.The correct set of quantum numbers for the unpaired electron of chloride atom is
n l m
Solution
(c) Cl(Z=18) [Ne]3s^2 3p^5 For the last electron: n=3,l=1,m=-1,0, or+1
(c) Cl(Z=18) [Ne]3s^2 3p^5 For the last electron: n=3,l=1,m=-1,0, or+1
Q10. The energy released during the fission of 1 kg of uranium is
Solution
(a)
E=mc^2
=m×931 MeV
(a)
E=mc^2
=m×931 MeV