The P-Block Quiz-18
Dear Readers,
IIT JEE exam which consists of JEE Main and JEE Advanced is one of the most important entrance exams for engineering aspirants. The exam is held for candidates who are aspiring to pursue a career in the field of engineering and technical studies.
Chemistry is important because everything you do is chemistry! Even your body is made of chemicals. Chemical reactions occur when you breathe, eat, or just sit there reading. All matter is made of chemicals, so the importance of chemistry is that it's the study of everything.
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Q1. Statement 1:All the noble gases have ns2np6 electronic configuration in their outermost shell
Statement 2:In noble gases all the energy levels which are occupied are completely filled
Statement 2:In noble gases all the energy levels which are occupied are completely filled
Solution
All the noble gases except He, have ns2np6 electronic configuration in their outermost shell
Q2.Statement 1: The aqueous solution of XeF2 is powerful oxidizing agent
Statement 2: The hydrolysis of XeF2 is show in dilute acid but rapid in basic solution
Solution
XeF2 oxidise HCl to Cl2 and Ce(III) to Ce (IV). Its oxidation potentials is +2.64 V
XeF2 oxidise HCl to Cl2 and Ce(III) to Ce (IV). Its oxidation potentials is +2.64 V
Q3. Statement 1:Liquid NH3 is used for refrigeration.
Statement 2:Liquid NH3 does not vaporize quickly.
Solution
Liquid ammonia has a large heat of vaporization (0.327 cal/g). It is therefore used in ice plants.
Liquid ammonia has a large heat of vaporization (0.327 cal/g). It is therefore used in ice plants.
Q4. Statement 1: Ozone is a powerful oxidizing agent in comparison to O2
Statement 2: Ozone is diamagnetic but O2 is paramagnetic
Solution
Due to the ease with which it can liberate nascent oxygen, O3 acts as a powerful oxidising agent.
O3 → O2+O
O2 → Paramagnetic due to presence of two unpaired electrons
Due to the ease with which it can liberate nascent oxygen, O3 acts as a powerful oxidising agent.
O3 → O2+O
O2 → Paramagnetic due to presence of two unpaired electrons
Q5.Statement 1: PCl5 and PbCl4 are thermally unstable
Statement 2: They produce same gas on thermal decomposition
Solution
PCl2 →∆ PCl3 + Cl2 PCl5 decomposes into PCl3 and Cl2 as in its structure two P-Cl axial bonds are longer than other three P-Cl equatorial bonds
PCl2 →∆ PCl3 + Cl2 PCl5 decomposes into PCl3 and Cl2 as in its structure two P-Cl axial bonds are longer than other three P-Cl equatorial bonds
