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Chemistry is important because everything you do is chemistry! Even your body is made of chemicals. Chemical reactions occur when you breathe, eat, or just sit there reading. All matter is made of chemicals, so the importance of chemistry is that it's the study of everything..
Q1. The commonn name, “cream of tartar” refers to
Solution
(b) part
Potassium antimonyl tartrate
(b) part
Potassium antimonyl tartrate
Q2.The alkalide ion is
Solution
(a) part
(a) Na^+ is alkalide ion
Na(1s^2 2s^2 2p^6 4s^1)← Paramagnetic due to unpaired electrons
Na^- (1s^2 2s^2 2p^6 3s^2)← Diamagnetic due to paired electrons
(a) part
(a) Na^+ is alkalide ion
Na(1s^2 2s^2 2p^6 4s^1)← Paramagnetic due to unpaired electrons
Na^- (1s^2 2s^2 2p^6 3s^2)← Diamagnetic due to paired electrons
Q3. Which is the most stable halide of alkali metal?
Solution
(a) part
(a) part
Q4. Choose the incorrect statement
Solution
(d)
2NaF+BeF2 → Na2[BeF4] ⇌ 2Na^(+) + [BeF4]^(2-) anion
(d)
2NaF+BeF2 → Na2[BeF4] ⇌ 2Na^(+) + [BeF4]^(2-) anion
Q5.Some of alkali metal salts are coloured. Na2CrO4-yellow, KMnO4-pink, K2MnO4-green. It is due to
Solution
(b) part
Alkali salts are colourless
NaCl colourless Na2CrO4-yellow since CrO4^(3-) is yellow
KCl colourless K2CrO4- yellow
KMnO4- pink since MnO4^- is pink
K2MnO4- green since MnO4^(2-) is green
(b) part
Alkali salts are colourless
NaCl colourless Na2CrO4-yellow since CrO4^(3-) is yellow
KCl colourless K2CrO4- yellow
KMnO4- pink since MnO4^- is pink
K2MnO4- green since MnO4^(2-) is green
Q6. When NO is passed into KOH solution, products are
Solution
(a) PART
KO2 (O2^- is paramagnetic due to one unpaired electron) NO2 (is paramagnetic due to one unpaired electron on N)
(a) PART
KO2 (O2^- is paramagnetic due to one unpaired electron) NO2 (is paramagnetic due to one unpaired electron on N)
Q7. Following are the ionization potential values of
(I_1 )899 kJ mol^(-1)
(I_2 )1757 kJ mol^(-1)
(I_3 )15000 kJ mol^(-1)
(I_1 )899 kJ mol^(-1)
(I_2 )1757 kJ mol^(-1)
(I_3 )15000 kJ mol^(-1)
Solution
(c)
(IE)_3 is very high indicates +2 oxidation state. Thus, Be
(c)
(IE)_3 is very high indicates +2 oxidation state. Thus, Be
Q8.
Which is the incorrect statement?
Solution
(b) part
2NaNO3 → 2NaNO2 + O2
(b) part
2NaNO3 → 2NaNO2 + O2
Q9.A basic refractory material among the following is
Solution
(d) part
(d) part
Q10. Which has least molar solubility in H2O?
Solution
(C) part
Molar solubility is in mol L^(-1) (Reference Concise) inorganic Chemistry J.D. Lee)
LiCl=19.6
NaCl=6.2
KCl=4.8
RbCl=7.5
CsCl=11.0
(C) part
Molar solubility is in mol L^(-1) (Reference Concise) inorganic Chemistry J.D. Lee)
LiCl=19.6
NaCl=6.2
KCl=4.8
RbCl=7.5
CsCl=11.0