Thermal Properties of Matter-Quiz-1

 

THERMAL PROPERTIES OF MATTER QUIZ-1

Dear Readers,

JEE Advanced Physics Syllabus can be referred by the IIT aspirants to get a detailed list of all topics that are important in cracking the entrance examination. JEE Advanced syllabus for Physics has been designed in such a way that it offers very practical and application-based learning to further make it easier for students to understand every concept or topic by correlating it with day-to-day experiences. In comparison to the other two subjects, the syllabus of JEE Advanced for physics is developed in such a way so as to test the deep understanding and application of concepts.

Q1. A rod of length l and cross-sectional area A has a variable conductively given by K=αT, where α is a positive constant and T is temperature in kelvin. Two ends of the rod are maintained at temperature T_1 and T_2 (T_1>T_2 ). Heat current flowing through the rod will be

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Solution

Q2. A glass flask is filled up to a mark with 50 cc of mercury at 18°C. If the flask and contents are heated to 38°C, how much mercury will be above the mark (α for glass is 9×10^(-6)/°C and coefficient of real expansion of mercury is 180×10^(-6)/°C)?

•  0.85 cc
•  0.46 cc
•  0.153 cc
•  0.05 cc

Solution

Q3. A piece of metal floats in mercury. The coefficients of volume expansion of the metal and mercury are γ1 and γ2, respectively. If the temperatures of both mercury and the metal are increased by ∆T, the fraction of the volume of the metal submerged in mercury changes by the factor of

•   (1+γ2 ∆T)/(1+γ1 ∆T)
•  1+γ2 ∆T
•  1+γ1 ∆T
•  (1+γ2 ∆T)/(1-γ1 ∆T)

Solution

Q4. Power radiated by a black body is P_0 and the wavelength corresponding to maximum energy is around λ_0. On changing the temperature of the black body, it was observed that the power radiated becomes 256/81 P_0. The shift in wavelength corresponding to the maximum energy will be

•  +λ_0/4
•  +λ_0/2
•  -λ_0/4
•  -λ_0/2

Solution

Q5. Three very large plates of same area are kept parallel and close to each other. They are considered as ideal black surfaces and have very high thermal conductivity. The first and third plates are maintained at temperatures 2T and 3T respectively. The temperature of the middle (i.e. second) plate under steady state condition is

•  (65/2)^(1/4) T
•  (97/4)^(1/4) T
•  (97/2)^(1/4) T
•  (97)^(1/4) T

Solution
 

Q6. A liquid of density 0.85 g/cm^3 flows through a calorimeter at the rate of 8.0 cm^3/s. Heat is added by means of a 250 W electric heating coil and a temperature difference of 15°C is established in steady-state conditions between the inflow and the outflow points of the liquid. The specific heat for the liquid will be

•  0.6 kcal/kgK
•  0.3 kcal/kgK
• 0.5 kcal/kgK
•  0.4 kcal/kgK

Solution

Q7. The absolute coefficient of expansion of a liquid is 7 times that the volume coefficient of expansion of the vessel. Then the ratio of absolute and apparent expansion of the liquid is

•  1/7
•  7/6
•  6/7
•  None of these

Solution

Q8. A metallic sphere having radius 0.08 m and mass m=10 kg is heated to a temperature of 227°C and suspended inside a box whose walls are at a temperature of 27°C. The maximum rate at which its temperature will fall is (take e=1, Stefan’s constant σ=5.8×10^(-8) Wm² K^(-4) and specific heat of the metal =90cal/kg/deg⁡〖J=4.2 J/cal)〗

•  0.055°C/s
•  0.066°C/s
•  0.044°C/s
•  0.03°C/s

Solution

Q9. Liquid helium is stored at its boiling point (4.2 K) in a spherical can, separated by a vacuum space from a surrounding shield which is maintained at the temperature of liquid nitrogen (77 K). If the can is 0.1m in radius and is blacked on the outside so that it acts as a black body, how much helium boils away per hour? (Latent heat of vapourization is 21 kJ/kg)

•  43 g/h
•  43 kg/h
•  4.3 g/h
•  43×10^(-3) g/h

Solution

Q10. The coefficient of apparent expansion of mercury in a glass vessel is 153×10^(-6)/°C and in a steel vessel is 114×10^(-6)/°C. If α for steel is 12×10^(-6)/°C, then that of glass is

•  9×10^(-6)/C
•  6×10^(-6)/C
•  36×10^(-6)/C
• 27×10^(-6)/C

Solution