IIT JEE exam which consists of JEE Main and JEE Advanced is one of the most important entrance exams for engineering aspirants. The exam is held for candidates who are aspiring to pursue a career in the field of engineering and technical studies.
Chemistry is important because everything you do is chemistry! Even your body is made of chemicals. Chemical reactions occur when you breathe, eat, or just sit there reading. All matter is made of chemicals, so the importance of chemistry is that it's the study of everything..
Chemistry is important because everything you do is chemistry! Even your body is made of chemicals. Chemical reactions occur when you breathe, eat, or just sit there reading. All matter is made of chemicals, so the importance of chemistry is that it's the study of everything..
Q1. If S+O2→SO2; ∆H=-298.2 kJ
SO2+12O2→SO3; ∆H=-98.7 kJ
SO3+H2O→H2SO4; ∆H=-130.2 kJ
H2+12O2H2O; ∆H=-287.3 kJ
Then the enthalpy of formation of H2SO4 at 298 K is:
SO2+12O2→SO3; ∆H=-98.7 kJ
SO3+H2O→H2SO4; ∆H=-130.2 kJ
H2+12O2H2O; ∆H=-287.3 kJ
Then the enthalpy of formation of H2SO4 at 298 K is:
Solution
-650.3 kJ
-650.3 kJ
Q2.The products of combustion of an aliphatic thiol (RSH) at 298 K are
Solution
CO2(g), H2O(l), and SO2(g)
CO2(g), H2O(l), and SO2(g)
Q3.For hypothetical reversible reaction
1/2A2(g)+3/2B2(g)→AB3(g); ∆H=-20kJ if standard entropies of A2,B2and AB3 are 60, 40, and 50 J K-1mol-1, respectively. The above reaction will be equilibrium at
1/2A2(g)+3/2B2(g)→AB3(g); ∆H=-20kJ if standard entropies of A2,B2and AB3 are 60, 40, and 50 J K-1mol-1, respectively. The above reaction will be equilibrium at
Solution
At equilibrium, ∆STotal = 0
∴ SP⊖-SR⊖ = 0
At equilibrium, ∆STotal = 0
∴ SP⊖-SR⊖ = 0
Q4.CP-CV=R. This R is
Solution
PV = RT at temperature T for one mole
PV+∆V=R(T+1) at temperature (T+1) for one mole
∴ P∆V = R
PV = RT at temperature T for one mole
PV+∆V=R(T+1) at temperature (T+1) for one mole
∴ P∆V = R
Q5.For which of the following equations, will ∆H be equal to ∆U?
Solution
∆H = ∆U+∆nRT
In (b), ∆n=0
∴ ∆H = ∆U
∆H = ∆U+∆nRT
In (b), ∆n=0
∴ ∆H = ∆U
Q6.A reaction, A+B⟶C+D+q, is found to have a positive entropy change, the reaction will be:
Solution
Possible at any temperature
Possible at any temperature
Q7.For the combustion reaction at 298 K
2Ag(s)+1/2O2(g)→2Ag2O(s)
Which of the following alternatives is correct?
Solution
∆H = ∆U+∆nRT
∆n = nP-nR
∴ ∆n = (2) - (5/2) = (-1/2)
∴ ∆H = ∆U - (1/2)RT
∴ ∆U = ∆H + (1/2)RT
Or ∴ ∆U > ∆H
∆H = ∆U+∆nRT
∆n = nP-nR
∴ ∆n = (2) - (5/2) = (-1/2)
∴ ∆H = ∆U - (1/2)RT
∴ ∆U = ∆H + (1/2)RT
Or ∴ ∆U > ∆H
Q8.Enthalpy of the system is given as
Solution
H = U + PV
H = U + PV
Q9.In thermodynamics, a process is called reversible when
Solution
The surroundings are always in equilibrium with the system
The surroundings are always in equilibrium with the system
Q10. For the reversible process, the value of ∆S is given by the expression
Solution
∆S=qrev/T
∆S=qrev/T