WAVE OPTICS QUIZ 6
Dear Readers,
JEE Advanced Physics Syllabus can be referred by the IIT aspirants to get
a detailed list of all topics that are important in cracking the entrance
examination. JEE Advanced syllabus for Physics has been designed in such a
way that it offers very practical and application-based learning to
further make it easier for students to understand every concept or topic
by correlating it with day-to-day experiences. In comparison to the other
two subjects, the syllabus of JEE Advanced for physics is developed in
such a way so as to test the deep understanding and application of
concepts..
Q1. One of the two slits in YDSE is painted over, so that is transmits only light waves having intensity half of
the intensity of light waves having intensity half of the intensity of the light waves through the other slit. As a result of this
Solution
Q2. A ray of light is incident on a thin film. As shown in figure, 𝑀 and 𝑁 are two reflected rays while 𝑃 and 𝑄
are two transmitted rays. Rays 𝑁 and 𝑄 undergo a phase change of 𝜋. Correct ordering of the refracting indices is
Solution
Q3. In YDSE, let 𝐴 and 𝐵 be two slits. Films of thickness 𝑡A and 𝑡B and refractive indices 𝜇A and 𝜇B are placed in front of 𝐴 and 𝐵, respectively. If 𝜇A𝑡A = 𝜇A𝑡B, then the central maxima will
Solution
Q4. In Young’s double-slit experiment, the 𝑦-coordinates of central maxima and 10th maxima are 2 cm and 5 cm, respectively. When the YDSE apparatus is immersed in a liquid of refractive index 1.5, the corresponding 𝑦-coordinates will be
Solution
Q5. In the adjacent diagram, 𝐶𝑃 represents a wavefront and 𝐴𝑂 and 𝐵𝑃, the corresponding two rays. Find the condition on θ for constructive interference at P between the ray 𝐵𝑃 and reflected ray 𝑂𝑃
Solution
Q6. Two coherent monochromatic light beams of intensities 𝐼 and 4𝐼 are superposed. The maximum and minimum possible intensities in the resulting beam are
Solution
Q7. In Young’s experiment, the distance between the slits is reduced to half and the distance between the slit and screen is doubled, then the fringe width
Solution
Q8. Young’s double slit experiment is carried out by using green, red and blue light, one color at a time. The fringe widths recorded are 𝛽G , 𝛽R and 𝛽B , respectively. Then
Solution
Q9. In a YDSE, 𝐷 = 1 m, 𝑑 = 1 mm and 𝜆 = 5000 nm. The distance of 100th maxima from the central maxima is
Solution
Q10. Calculate the wavelength of light used in an interference experiment from the following data: Fringe width = 0.03 cm. Distance between slits and eyepiece through which the interference pattern is observed is 1 m. Distance between the images of the virtual source when a convex lens of focal length 16 cm is used at a distance of 80 cm from the eyepiece is 0.8 cm
Solution
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